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(2x+1)/(5x-3)=1
We move all terms to the left:
(2x+1)/(5x-3)-(1)=0
Domain of the equation: (5x-3)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
5x!=3
x!=3/5
x!=3/5
x∈R
(2x+1)-1*(5x-3)=0
We get rid of parentheses
2x-1*(5x-3)+1=0
We move all terms containing x to the left, all other terms to the right
2x-1*(5x-3)=-1
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