3/4x-1/20=7/10x=1

Solution for 3/4x-1/20=7/10x=1 equation:

3/4x-1/20=7/10x=1

We move all terms to the left:

3/4x-1/20-(7/10x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 10x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3/4x-(+7/10x)-1/20=0

We get rid of parentheses

3/4x-7/10x-1/20=0

We calculate fractions


(-40x^2)/1600x^2+1200x/1600x^2+(-1120x)/1600x^2=0

We multiply all the terms by the denominator


(-40x^2)+1200x+(-1120x)=0

We get rid of parentheses

-40x^2+1200x-1120x=0

We add all the numbers together, and all the variables

-40x^2+80x=0

a = -40; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·(-40)·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*-40}=\frac{-160}{-80}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*-40}=\frac{0}{-80}
=0
$