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3(x+1)-4=2(x-5)+4x
We move all terms to the left:
3(x+1)-4-(2(x-5)+4x)=0
We multiply parentheses
3x-(2(x-5)+4x)+3-4=0
We calculate terms in parentheses: -(2(x-5)+4x), so:We add all the numbers together, and all the variables
2(x-5)+4x
We add all the numbers together, and all the variables
4x+2(x-5)
We multiply parentheses
4x+2x-10
We add all the numbers together, and all the variables
6x-10
Back to the equation:
-(6x-10)
3x-(6x-10)-1=0
We get rid of parentheses
3x-6x+10-1=0
We add all the numbers together, and all the variables
-3x+9=0
We move all terms containing x to the left, all other terms to the right
-3x=-9
x=-9/-3
x=+3
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