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3/4x+5=1/2(x-8
We move all terms to the left:
3/4x+5-(1/2(x-8)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2(x-8)+5!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
2(x-8)!=-5
x∈R
(6x(x+5)/(8x^2(x+5)+(-(1*4x)/(8x^2(x+5)=0
We calculate terms in parentheses: +(6x(x+5)/(8x^2(x+5)+(-(1*4x)/(8x^2(x+5), so:
6x(x+5)/(8x^2(x+5)+(-(1*4x)/(8x^2(x+5
We can not solve this equation
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