(20*20)+(48*48)=(x*x)

Solution for (20*20)+(48*48)=(x*x) equation:

(20*20)+(48*48)=(x*x)

We move all terms to the left:

(20*20)+(48*48)-((x*x))=0

We add all the numbers together, and all the variables

-((+x*x))+400+2304=0

We add all the numbers together, and all the variables

-((+x*x))+2704=0


We calculate terms in parentheses: -((+x*x)), so:

(+x*x)

We get rid of parentheses

x*x

Wy multiply elements

x^2

Back to the equation:

-(x^2)


We add all the numbers together, and all the variables

-1x^2+2704=0

a = -1; b = 0; c = +2704;
Δ = b2-4ac
Δ = 02-4·(-1)·2704
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-104}{2*-1}=\frac{-104}{-2}
=+52
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+104}{2*-1}=\frac{104}{-2}
=-52
$