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3/4x+2+x=50
We move all terms to the left:
3/4x+2+x-(50)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
x+3/4x-48=0
We multiply all the terms by the denominator
x*4x-48*4x+3=0
Wy multiply elements
4x^2-192x+3=0
a = 4; b = -192; c = +3;
Δ = b2-4ac
Δ = -1922-4·4·3
Δ = 36816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{36816}=\sqrt{16*2301}=\sqrt{16}*\sqrt{2301}=4\sqrt{2301}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-192)-4\sqrt{2301}}{2*4}=\frac{192-4\sqrt{2301}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-192)+4\sqrt{2301}}{2*4}=\frac{192+4\sqrt{2301}}{8} $
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