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3/4x+1/2=-5-2/3x
We move all terms to the left:
3/4x+1/2-(-5-2/3x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/4x-(-2/3x-5)+1/2=0
We get rid of parentheses
3/4x+2/3x+5+1/2=0
We calculate fractions
36x^2/48x^2+36x/48x^2+32x/48x^2+5=0
We multiply all the terms by the denominator
36x^2+36x+32x+5*48x^2=0
We add all the numbers together, and all the variables
36x^2+68x+5*48x^2=0
Wy multiply elements
36x^2+240x^2+68x=0
We add all the numbers together, and all the variables
276x^2+68x=0
a = 276; b = 68; c = 0;
Δ = b2-4ac
Δ = 682-4·276·0
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-68}{2*276}=\frac{-136}{552} =-17/69 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+68}{2*276}=\frac{0}{552} =0 $
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