12g=(122/3g-1)+11

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Solution for 12g=(122/3g-1)+11 equation: 



12g=(122/3g-1)+11

We move all terms to the left:

12g-((122/3g-1)+11)=0



Domain of the equation: 3g-1)+11)!=0

g∈R



We multiply all the terms by the denominator


12g*3g-1)+11)-((122=0

We add all the numbers together, and all the variables

12g*3g=0

Wy multiply elements

36g^2=0

a = 36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·36·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$g=\frac{-b}{2a}=\frac{0}{72}=0$

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