3/4k-(k+1/4)=1/16(k+1)

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Solution for 3/4k-(k+1/4)=1/16(k+1) equation: 



3/4k-(k+1/4)=1/16(k+1)

We move all terms to the left:

3/4k-(k+1/4)-(1/16(k+1))=0



Domain of the equation: 4k!=0

k!=0/4

k!=0

k∈R





Domain of the equation: 16(k+1))!=0

k∈R



We add all the numbers together, and all the variables

3/4k-(+k+1/4)-(1/16(k+1))=0

We get rid of parentheses

3/4k-k-(1/16(k+1))-1/4=0

We calculate fractions


-k+(48kk/(256k^2k+(-(1*4k*4)/(256k^2k+(-16kk/(256k^2k=0

We can not solve this equation

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