2x2=98x

Solution for 2x2=98x equation:

2x^2=98x

We move all terms to the left:

2x^2-(98x)=0

a = 2; b = -98; c = 0;
Δ = b2-4ac
Δ = -982-4·2·0
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-98}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+98}{2*2}=\frac{196}{4}
=49
$