3/4h-1/3h=3/8

Solution for 3/4h-1/3h=3/8 equation:

3/4h-1/3h=3/8

We move all terms to the left:

3/4h-1/3h-(3/8)=0


Domain of the equation: 4h!=0

h!=0/4

h!=0

h∈R



Domain of the equation: 3h!=0

h!=0/3

h!=0

h∈R


We add all the numbers together, and all the variables

3/4h-1/3h-(+3/8)=0

We get rid of parentheses

3/4h-1/3h-3/8=0

We calculate fractions


(-108h^2)/768h^2+576h/768h^2+(-256h)/768h^2=0

We multiply all the terms by the denominator


(-108h^2)+576h+(-256h)=0

We get rid of parentheses

-108h^2+576h-256h=0

We add all the numbers together, and all the variables

-108h^2+320h=0

a = -108; b = 320; c = 0;
Δ = b2-4ac
Δ = 3202-4·(-108)·0
Δ = 102400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{102400}=320$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(320)-320}{2*-108}=\frac{-640}{-216}
=2+26/27
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(320)+320}{2*-108}=\frac{0}{-216}
=0
$