5(r-2)-3r=7(r+3)+9

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Solution for 5(r-2)-3r=7(r+3)+9 equation: 



5(r-2)-3r=7(r+3)+9

We move all terms to the left:

5(r-2)-3r-(7(r+3)+9)=0

We add all the numbers together, and all the variables

-3r+5(r-2)-(7(r+3)+9)=0

We multiply parentheses

-3r+5r-(7(r+3)+9)-10=0



We calculate terms in parentheses: -(7(r+3)+9), so:

7(r+3)+9

We multiply parentheses

7r+21+9

We add all the numbers together, and all the variables

7r+30

Back to the equation:

-(7r+30)



We add all the numbers together, and all the variables

2r-(7r+30)-10=0

We get rid of parentheses

2r-7r-30-10=0

We add all the numbers together, and all the variables

-5r-40=0

We move all terms containing r to the left, all other terms to the right

-5r=40

r=40/-5

r=-8

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