3/4h+9=1/2h*8

Solution for 3/4h+9=1/2h*8 equation:

3/4h+9=1/2h*8

We move all terms to the left:

3/4h+9-(1/2h*8)=0


Domain of the equation: 4h!=0

h!=0/4

h!=0

h∈R



Domain of the equation: 2h*8)!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

3/4h-(+1/2h*8)+9=0

We get rid of parentheses

3/4h-1/2h*8+9=0

We calculate fractions


384h/512h^2+(-4h)/512h^2+9=0

We multiply all the terms by the denominator


384h+(-4h)+9*512h^2=0

Wy multiply elements

4608h^2+384h+(-4h)=0

We get rid of parentheses

4608h^2+384h-4h=0

We add all the numbers together, and all the variables

4608h^2+380h=0

a = 4608; b = 380; c = 0;
Δ = b2-4ac
Δ = 3802-4·4608·0
Δ = 144400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144400}=380$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(380)-380}{2*4608}=\frac{-760}{9216}
=-95/1152
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(380)+380}{2*4608}=\frac{0}{9216}
=0
$