-2(c-4)+6=11+2c-5

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Solution for -2(c-4)+6=11+2c-5 equation: 



-2(c-4)+6=11+2c-5

We move all terms to the left:

-2(c-4)+6-(11+2c-5)=0

We add all the numbers together, and all the variables

-2(c-4)-(2c+6)+6=0

We multiply parentheses

-2c-(2c+6)+8+6=0

We get rid of parentheses

-2c-2c-6+8+6=0

We add all the numbers together, and all the variables

-4c+8=0

We move all terms containing c to the left, all other terms to the right

-4c=-8

c=-8/-4

c=+2

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