3/4h+6-h=-2

Solution for 3/4h+6-h=-2 equation:

3/4h+6-h=-2

We move all terms to the left:

3/4h+6-h-(-2)=0


Domain of the equation: 4h!=0

h!=0/4

h!=0

h∈R


We add all the numbers together, and all the variables

-1h+3/4h+8=0

We multiply all the terms by the denominator


-1h*4h+8*4h+3=0

Wy multiply elements

-4h^2+32h+3=0

a = -4; b = 32; c = +3;
Δ = b2-4ac
Δ = 322-4·(-4)·3
Δ = 1072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1072}=\sqrt{16*67}=\sqrt{16}*\sqrt{67}=4\sqrt{67}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-4\sqrt{67}}{2*-4}=\frac{-32-4\sqrt{67}}{-8}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+4\sqrt{67}}{2*-4}=\frac{-32+4\sqrt{67}}{-8}
$