4(5y-2)=11(2y-6)

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Solution for 4(5y-2)=11(2y-6) equation: 



4(5y-2)=11(2y-6)

We move all terms to the left:

4(5y-2)-(11(2y-6))=0

We multiply parentheses

20y-(11(2y-6))-8=0



We calculate terms in parentheses: -(11(2y-6)), so:

11(2y-6)

We multiply parentheses

22y-66

Back to the equation:

-(22y-66)



We get rid of parentheses

20y-22y+66-8=0

We add all the numbers together, and all the variables

-2y+58=0

We move all terms containing y to the left, all other terms to the right

-2y=-58

y=-58/-2

y=+29

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