3/4b-5=16

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Solution for 3/4b-5=16 equation: 



3/4b-5=16

We move all terms to the left:

3/4b-5-(16)=0



Domain of the equation: 4b!=0

b!=0/4

b!=0

b∈R



We add all the numbers together, and all the variables

3/4b-21=0

We multiply all the terms by the denominator


-21*4b+3=0

Wy multiply elements

-84b+3=0

We move all terms containing b to the left, all other terms to the right

-84b=-3

b=-3/-84

b=1/28

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