3/4b-2=-7/-8b+3

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Solution for 3/4b-2=-7/-8b+3 equation: 


b in (-oo:+oo)

(3/4)*b-2 = (-7/(-8))*b+3 // - (-7/(-8))*b+3

(3/4)*b-((-7/(-8))*b)-3-2 = 0

(3/4)*b+(-7/8)*b-3-2 = 0

-1/8*b-5 = 0 // + 5

-1/8*b = 5 // : -1/8

b = 5/(-1/8)

b = -40

b = -40

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