3/4(8t-12)=6(t-1)

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Solution for 3/4(8t-12)=6(t-1) equation: 


t in (-oo:+oo)

(3/4)*(8*t-12) = 6*(t-1) // - 6*(t-1)

(3/4)*(8*t-12)-(6*(t-1)) = 0

(3/4)*(8*t-12)-6*(t-1) = 0

3/4*(8*t-12)-6*(t-1) = 0

3/4*(8*t-12)-6*(t-1) = 0

-3 = 0

-3 = 0

t belongs to the empty set

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