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3/4(z-2)-1/3(2z-5)=-2
We move all terms to the left:
3/4(z-2)-1/3(2z-5)-(-2)=0
Domain of the equation: 4(z-2)!=0
z∈R
Domain of the equation: 3(2z-5)!=0We add all the numbers together, and all the variables
z∈R
3/4(z-2)-1/3(2z-5)+2=0
We calculate fractions
(9z2/(4(z-2)*3(2z-5))+(-4zz/(4(z-2)*3(2z-5))+2=0
We can not solve this equation
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