2(x+3)2=(x+2)2=16

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Solution for 2(x+3)2=(x+2)2=16 equation: 



2(x+3)2=(x+2)2=16

We move all terms to the left:

2(x+3)2-((x+2)2)=0

We multiply parentheses

4x-((x+2)2)+12=0



We calculate terms in parentheses: -((x+2)2), so:

(x+2)2

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)



We get rid of parentheses

4x-2x-4+12=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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