3/4(n+3)=-1/6(n+45)

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Solution for 3/4(n+3)=-1/6(n+45) equation: 



3/4(n+3)=-1/6(n+45)

We move all terms to the left:

3/4(n+3)-(-1/6(n+45))=0



Domain of the equation: 4(n+3)!=0

n∈R





Domain of the equation: 6(n+45))!=0

n∈R



We calculate fractions


(18nn/(4(n+3)*6(n+45)))+(-(-4nn)/(4(n+3)*6(n+45)))=0



We calculate terms in parentheses: +(18nn/(4(n+3)*6(n+45))), so:

18nn/(4(n+3)*6(n+45))

We multiply all the terms by the denominator


18nn

Back to the equation:

+(18nn)





We calculate terms in parentheses: +(-(-4nn)/(4(n+3)*6(n+45))), so:

-(-4nn)/(4(n+3)*6(n+45))

We multiply all the terms by the denominator


-(-4nn)

We get rid of parentheses

4nn

Back to the equation:

+(4nn)

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