7(k-5)-(6k+5)=3

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Solution for 7(k-5)-(6k+5)=3 equation: 



7(k-5)-(6k+5)=3

We move all terms to the left:

7(k-5)-(6k+5)-(3)=0

We multiply parentheses

7k-(6k+5)-35-3=0

We get rid of parentheses

7k-6k-5-35-3=0

We add all the numbers together, and all the variables

k-43=0

We move all terms containing k to the left, all other terms to the right

k=43

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