3/4(8x-4)+2x-1=1/2(16x+18)

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Solution for 3/4(8x-4)+2x-1=1/2(16x+18) equation: 



3/4(8x-4)+2x-1=1/2(16x+18)

We move all terms to the left:

3/4(8x-4)+2x-1-(1/2(16x+18))=0



Domain of the equation: 4(8x-4)!=0

x∈R





Domain of the equation: 2(16x+18))!=0

x∈R



We add all the numbers together, and all the variables

2x+3/4(8x-4)-(1/2(16x+18))-1=0

We calculate fractions


2x+(6x1/(4(8x-4)*2(16x+18)))+(-4x8/(4(8x-4)*2(16x+18)))-1=0



We calculate terms in parentheses: +(6x1/(4(8x-4)*2(16x+18))), so:

6x1/(4(8x-4)*2(16x+18))

We multiply all the terms by the denominator


6x1

We add all the numbers together, and all the variables

6x

Back to the equation:

+(6x)





We calculate terms in parentheses: +(-4x8/(4(8x-4)*2(16x+18))), so:

-4x8/(4(8x-4)*2(16x+18))

We multiply all the terms by the denominator


-4x8

We add all the numbers together, and all the variables

-4x^8

We do not support expression: x^8

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