8-2(3x-3)=10-(6-3x)

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Solution for 8-2(3x-3)=10-(6-3x) equation: 



8-2(3x-3)=10-(6-3x)

We move all terms to the left:

8-2(3x-3)-(10-(6-3x))=0

We add all the numbers together, and all the variables

-2(3x-3)-(10-(-3x+6))+8=0

We multiply parentheses

-6x-(10-(-3x+6))+6+8=0



We calculate terms in parentheses: -(10-(-3x+6)), so:

10-(-3x+6)

determiningTheFunctionDomain
-(-3x+6)+10

We get rid of parentheses

3x-6+10

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We add all the numbers together, and all the variables

-6x-(3x+4)+14=0

We get rid of parentheses

-6x-3x-4+14=0

We add all the numbers together, and all the variables

-9x+10=0

We move all terms containing x to the left, all other terms to the right

-9x=-10

x=-10/-9

x=1+1/9

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