3/4(8d-4)=7/3(6+3d)

Solution for 3/4(8d-4)=7/3(6+3d) equation:

3/4(8d-4)=7/3(6+3d)

We move all terms to the left:

3/4(8d-4)-(7/3(6+3d))=0


Domain of the equation: 4(8d-4)!=0

d∈R



Domain of the equation: 3(6+3d))!=0

d∈R


We add all the numbers together, and all the variables

3/4(8d-4)-(7/3(3d+6))=0

We calculate fractions


(9d3/(4(8d-4)*3(3d+6)))+(-28d8/(4(8d-4)*3(3d+6)))=0


We calculate terms in parentheses: +(9d3/(4(8d-4)*3(3d+6))), so:

9d3/(4(8d-4)*3(3d+6))

We multiply all the terms by the denominator


9d3

We add all the numbers together, and all the variables

9d^3

We do not support edpression: d^3