3/4(8+4n)-9=1/3(6n+3)

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Solution for 3/4(8+4n)-9=1/3(6n+3) equation: 



3/4(8+4n)-9=1/3(6n+3)

We move all terms to the left:

3/4(8+4n)-9-(1/3(6n+3))=0



Domain of the equation: 4(8+4n)!=0

n∈R





Domain of the equation: 3(6n+3))!=0

n∈R



We add all the numbers together, and all the variables

3/4(4n+8)-(1/3(6n+3))-9=0

We calculate fractions


(9n6/(4(4n+8)*3(6n+3)))+(-4n4/(4(4n+8)*3(6n+3)))-9=0



We calculate terms in parentheses: +(9n6/(4(4n+8)*3(6n+3))), so:

9n6/(4(4n+8)*3(6n+3))

We multiply all the terms by the denominator


9n6

We add all the numbers together, and all the variables

9n^6

We do not support enpression: n^6

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