3/4(6-x)=10+2x

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Solution for 3/4(6-x)=10+2x equation: 



3/4(6-x)=10+2x

We move all terms to the left:

3/4(6-x)-(10+2x)=0



Domain of the equation: 4(6-x)!=0

x∈R



We add all the numbers together, and all the variables

3/4(-1x+6)-(2x+10)=0

We get rid of parentheses

3/4(-1x+6)-2x-10=0

We multiply all the terms by the denominator


-2x*4(-1x+6)-10*4(-1x+6)+3=0

Wy multiply elements

-8x^2(--40x(-+3=0

We use the square of the difference formula

-8x^2(+40x(-3=0

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