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(1)/(2)(3x+1+15)=12.5
We move all terms to the left:
(1)/(2)(3x+1+15)-(12.5)=0
Domain of the equation: 2(3x+1+15)!=0We add all the numbers together, and all the variables
x∈R
1/2(3x+16)-(12.5)=0
We add all the numbers together, and all the variables
1/2(3x+16)-12.5=0
We multiply all the terms by the denominator
-(12.5)*2(3x+16)+1=0
We move all terms containing x to the left, all other terms to the right
-(12.5)*2(3x+16)=-1
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