3/4(4x+8)=1/2(2x-10)

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Solution for 3/4(4x+8)=1/2(2x-10) equation: 



3/4(4x+8)=1/2(2x-10)

We move all terms to the left:

3/4(4x+8)-(1/2(2x-10))=0



Domain of the equation: 4(4x+8)!=0

x∈R





Domain of the equation: 2(2x-10))!=0

x∈R



We calculate fractions


(6x2/(4(4x+8)*2(2x-10)))+(-4x4/(4(4x+8)*2(2x-10)))=0



We calculate terms in parentheses: +(6x2/(4(4x+8)*2(2x-10))), so:

6x2/(4(4x+8)*2(2x-10))

We multiply all the terms by the denominator


6x2

We add all the numbers together, and all the variables

6x^2

Back to the equation:

+(6x^2)





We calculate terms in parentheses: +(-4x4/(4(4x+8)*2(2x-10))), so:

-4x4/(4(4x+8)*2(2x-10))

We multiply all the terms by the denominator


-4x4

We add all the numbers together, and all the variables

-4x^4

We do not support expression: x^4

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