(40-3x)/5=(6x+7)/8

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Solution for (40-3x)/5=(6x+7)/8 equation: 



(40-3x)/5=(6x+7)/8

We move all terms to the left:

(40-3x)/5-((6x+7)/8)=0

We add all the numbers together, and all the variables

(-3x+40)/5-((6x+7)/8)=0

We calculate fractions


(-3x)/()+(-((6x+7)*5)/()=0



We calculate terms in parentheses: +(-((6x+7)*5)/(), so:

-((6x+7)*5)/(

We multiply all the terms by the denominator


-((6x+7)*5)



We calculate terms in parentheses: -((6x+7)*5), so:

(6x+7)*5

We multiply parentheses

30x+35

Back to the equation:

-(30x+35)



We get rid of parentheses

-30x-35

Back to the equation:

+(-30x-35)



We get rid of parentheses

(-3x)/()-30x-35=0

We multiply all the terms by the denominator


(-3x)-30x*()-35*()=0

We add all the numbers together, and all the variables

(-3x)-30x*()=0

We get rid of parentheses

-3x-30x*()=0

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