3/4(4x+8)-6x=2x-1/2(12-2x)

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Solution for 3/4(4x+8)-6x=2x-1/2(12-2x) equation:



3/4(4x+8)-6x=2x-1/2(12-2x)
We move all terms to the left:
3/4(4x+8)-6x-(2x-1/2(12-2x))=0
Domain of the equation: 4(4x+8)!=0
x∈R
Domain of the equation: 2(12-2x))!=0
x∈R
We add all the numbers together, and all the variables
3/4(4x+8)-6x-(2x-1/2(-2x+12))=0
We add all the numbers together, and all the variables
-6x+3/4(4x+8)-(2x-1/2(-2x+12))=0
We calculate fractions
-6x+(6x(-)/(4(4x+8)*2(-2x+12)))+(-(2x-4x4)/(4(4x+8)*2(-2x+12)))=0
We calculate terms in parentheses: +(6x(-)/(4(4x+8)*2(-2x+12))), so:
6x(-)/(4(4x+8)*2(-2x+12))
We add all the numbers together, and all the variables
6x0/(4(4x+8)*2(-2x+12))
We multiply all the terms by the denominator
6x0
We add all the numbers together, and all the variables
6x
Back to the equation:
+(6x)
We calculate terms in parentheses: +(-(2x-4x4)/(4(4x+8)*2(-2x+12))), so:
-(2x-4x4)/(4(4x+8)*2(-2x+12))
We add all the numbers together, and all the variables
-(+2x-4x^4)/(4(4x+8)*2(-2x+12))
We multiply all the terms by the denominator
-(+2x-4x^4)
We do not support expression: x^4

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