2(w-1)+4w=3(w+1)+7

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Solution for 2(w-1)+4w=3(w+1)+7 equation: 



2(w-1)+4w=3(w+1)+7

We move all terms to the left:

2(w-1)+4w-(3(w+1)+7)=0

We add all the numbers together, and all the variables

4w+2(w-1)-(3(w+1)+7)=0

We multiply parentheses

4w+2w-(3(w+1)+7)-2=0



We calculate terms in parentheses: -(3(w+1)+7), so:

3(w+1)+7

We multiply parentheses

3w+3+7

We add all the numbers together, and all the variables

3w+10

Back to the equation:

-(3w+10)



We add all the numbers together, and all the variables

6w-(3w+10)-2=0

We get rid of parentheses

6w-3w-10-2=0

We add all the numbers together, and all the variables

3w-12=0

We move all terms containing w to the left, all other terms to the right

3w=12

w=12/3

w=4

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