3/4(4x+12)=6+1/3(9x-3)

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Solution for 3/4(4x+12)=6+1/3(9x-3) equation:



3/4(4x+12)=6+1/3(9x-3)
We move all terms to the left:
3/4(4x+12)-(6+1/3(9x-3))=0
Domain of the equation: 4(4x+12)!=0
x∈R
Domain of the equation: 3(9x-3))!=0
x∈R
We calculate fractions
(9x9/(4(4x+12)*3(9x-3)))+(-4x4/(4(4x+12)*3(9x-3)))=0
We calculate terms in parentheses: +(9x9/(4(4x+12)*3(9x-3))), so:
9x9/(4(4x+12)*3(9x-3))
We multiply all the terms by the denominator
9x9
We add all the numbers together, and all the variables
9x^9
We do not support expression: x^9

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