8x+2=4(x+1)+x-2

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Solution for 8x+2=4(x+1)+x-2 equation: 



8x+2=4(x+1)+x-2

We move all terms to the left:

8x+2-(4(x+1)+x-2)=0



We calculate terms in parentheses: -(4(x+1)+x-2), so:

4(x+1)+x-2

We add all the numbers together, and all the variables

x+4(x+1)-2

We multiply parentheses

x+4x+4-2

We add all the numbers together, and all the variables

5x+2

Back to the equation:

-(5x+2)



We get rid of parentheses

8x-5x-2+2=0

We add all the numbers together, and all the variables

3x=0

x=0/3

x=0

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