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3/4(2a-6)+1/2=2/3(3a+20)
We move all terms to the left:
3/4(2a-6)+1/2-(2/3(3a+20))=0
Domain of the equation: 4(2a-6)!=0
a∈R
Domain of the equation: 3(3a+20))!=0We calculate fractions
a∈R
(18a3/(4(2a-6)*3(3a+20))*2)+(-(2*4(2a-6)*2)/(4(2a-6)*3(3a+20))*2)+(12a^22/(4(2a-6)*3(3a+20))*2)=0
We calculate terms in parentheses: +(18a3/(4(2a-6)*3(3a+20))*2), so:
18a3/(4(2a-6)*3(3a+20))*2
We multiply all the terms by the denominator
18a3
We add all the numbers together, and all the variables
18a^3
We do not support eapression: a^3
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