p2=1024

Solution for p2=1024 equation:

p2=1024

We move all terms to the left:

p2-(1024)=0

We add all the numbers together, and all the variables

p^2-1024=0

a = 1; b = 0; c = -1024;
Δ = b2-4ac
Δ = 02-4·1·(-1024)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64}{2*1}=\frac{-64}{2}
=-32
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64}{2*1}=\frac{64}{2}
=32
$