3/4(16x+12)-2=-1/5(10x-40)

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Solution for 3/4(16x+12)-2=-1/5(10x-40) equation: 



3/4(16x+12)-2=-1/5(10x-40)

We move all terms to the left:

3/4(16x+12)-2-(-1/5(10x-40))=0



Domain of the equation: 4(16x+12)!=0

x∈R





Domain of the equation: 5(10x-40))!=0

x∈R



We calculate fractions


(15x1/(4(16x+12)*5(10x-40)))+(-(-4x1)/(4(16x+12)*5(10x-40)))-2=0



We calculate terms in parentheses: +(15x1/(4(16x+12)*5(10x-40))), so:

15x1/(4(16x+12)*5(10x-40))

We multiply all the terms by the denominator


15x1

We add all the numbers together, and all the variables

15x

Back to the equation:

+(15x)





We calculate terms in parentheses: +(-(-4x1)/(4(16x+12)*5(10x-40))), so:

-(-4x1)/(4(16x+12)*5(10x-40))

We add all the numbers together, and all the variables

-(-4x)/(4(16x+12)*5(10x-40))

We multiply all the terms by the denominator


-(-4x)

We get rid of parentheses

4x

Back to the equation:

+(4x)



We add all the numbers together, and all the variables

19x-2=0

We move all terms containing x to the left, all other terms to the right

19x=2

x=2/19

x=2/19

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