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3/2y-5=15-y
We move all terms to the left:
3/2y-5-(15-y)=0
Domain of the equation: 2y!=0We add all the numbers together, and all the variables
y!=0/2
y!=0
y∈R
3/2y-(-1y+15)-5=0
We get rid of parentheses
3/2y+1y-15-5=0
We multiply all the terms by the denominator
1y*2y-15*2y-5*2y+3=0
Wy multiply elements
2y^2-30y-10y+3=0
We add all the numbers together, and all the variables
2y^2-40y+3=0
a = 2; b = -40; c = +3;
Δ = b2-4ac
Δ = -402-4·2·3
Δ = 1576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1576}=\sqrt{4*394}=\sqrt{4}*\sqrt{394}=2\sqrt{394}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-2\sqrt{394}}{2*2}=\frac{40-2\sqrt{394}}{4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+2\sqrt{394}}{2*2}=\frac{40+2\sqrt{394}}{4} $
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