6(b+3)+3=-(3b-3)

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Solution for 6(b+3)+3=-(3b-3) equation: 



6(b+3)+3=-(3b-3)

We move all terms to the left:

6(b+3)+3-(-(3b-3))=0

We multiply parentheses

6b-(-(3b-3))+18+3=0



We calculate terms in parentheses: -(-(3b-3)), so:

-(3b-3)

We get rid of parentheses

-3b+3

Back to the equation:

-(-3b+3)



We add all the numbers together, and all the variables

6b-(-3b+3)+21=0

We get rid of parentheses

6b+3b-3+21=0

We add all the numbers together, and all the variables

9b+18=0

We move all terms containing b to the left, all other terms to the right

9b=-18

b=-18/9

b=-2

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