3/2x+10=19

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Solution for 3/2x+10=19 equation: 



3/2x+10=19

We move all terms to the left:

3/2x+10-(19)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



We add all the numbers together, and all the variables

3/2x-9=0

We multiply all the terms by the denominator


-9*2x+3=0

Wy multiply elements

-18x+3=0

We move all terms containing x to the left, all other terms to the right

-18x=-3

x=-3/-18

x=1/6

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