3/2q+6=10

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Solution for 3/2q+6=10 equation: 



3/2q+6=10

We move all terms to the left:

3/2q+6-(10)=0



Domain of the equation: 2q!=0

q!=0/2

q!=0

q∈R



We add all the numbers together, and all the variables

3/2q-4=0

We multiply all the terms by the denominator


-4*2q+3=0

Wy multiply elements

-8q+3=0

We move all terms containing q to the left, all other terms to the right

-8q=-3

q=-3/-8

q=3/8

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