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11(v+2)-2v=3(3v+1)-10
We move all terms to the left:
11(v+2)-2v-(3(3v+1)-10)=0
We add all the numbers together, and all the variables
-2v+11(v+2)-(3(3v+1)-10)=0
We multiply parentheses
-2v+11v-(3(3v+1)-10)+22=0
We calculate terms in parentheses: -(3(3v+1)-10), so:We add all the numbers together, and all the variables
3(3v+1)-10
We multiply parentheses
9v+3-10
We add all the numbers together, and all the variables
9v-7
Back to the equation:
-(9v-7)
9v-(9v-7)+22=0
We get rid of parentheses
9v-9v+7+22=0
We add all the numbers together, and all the variables
29!=0
There is no solution for this equation
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