3/2(d+12)=1/2(3d-6)

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Solution for 3/2(d+12)=1/2(3d-6) equation:



3/2(d+12)=1/2(3d-6)
We move all terms to the left:
3/2(d+12)-(1/2(3d-6))=0
Domain of the equation: 2(d+12)!=0
d∈R
Domain of the equation: 2(3d-6))!=0
d∈R
We calculate fractions
(6d3/(2(d+12)*2(3d-6)))+(-2dd/(2(d+12)*2(3d-6)))=0
We calculate terms in parentheses: +(6d3/(2(d+12)*2(3d-6))), so:
6d3/(2(d+12)*2(3d-6))
We multiply all the terms by the denominator
6d3
We add all the numbers together, and all the variables
6d^3
We do not support edpression: d^3

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