(d-3)(d-2)=3d+d2-5

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Solution for (d-3)(d-2)=3d+d2-5 equation:



(d-3)(d-2)=3d+d2-5
We move all terms to the left:
(d-3)(d-2)-(3d+d2-5)=0
We add all the numbers together, and all the variables
-(+3d+d^2-5)+(d-3)(d-2)=0
We get rid of parentheses
-d^2-3d+(d-3)(d-2)+5=0
We multiply parentheses ..
-d^2+(+d^2-2d-3d+6)-3d+5=0
We add all the numbers together, and all the variables
-1d^2+(+d^2-2d-3d+6)-3d+5=0
We get rid of parentheses
-1d^2+d^2-2d-3d-3d+6+5=0
We add all the numbers together, and all the variables
-8d+11=0
We move all terms containing d to the left, all other terms to the right
-8d=-11
d=-11/-8
d=1+3/8

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