3/2(7+3b)=3+3b

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Solution for 3/2(7+3b)=3+3b equation: 



3/2(7+3b)=3+3b

We move all terms to the left:

3/2(7+3b)-(3+3b)=0



Domain of the equation: 2(7+3b)!=0

b∈R



We add all the numbers together, and all the variables

3/2(3b+7)-(3b+3)=0

We get rid of parentheses

3/2(3b+7)-3b-3=0

We multiply all the terms by the denominator


-3b*2(3b+7)-3*2(3b+7)+3=0

Wy multiply elements

-6b^2(3-6b(3+3=0

We do not support ebpression: b^2(3

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