5/12(t-4)=10

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Solution for 5/12(t-4)=10 equation: 



5/12(t-4)=10

We move all terms to the left:

5/12(t-4)-(10)=0



Domain of the equation: 12(t-4)!=0

t∈R



We multiply all the terms by the denominator


-10*12(t-4)+5=0

Wy multiply elements

-120t(t+5=0

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