3/2(4x+2)=5/2(2x-2)

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Solution for 3/2(4x+2)=5/2(2x-2) equation:



3/2(4x+2)=5/2(2x-2)
We move all terms to the left:
3/2(4x+2)-(5/2(2x-2))=0
Domain of the equation: 2(4x+2)!=0
x∈R
Domain of the equation: 2(2x-2))!=0
x∈R
We calculate fractions
(6x2/(2(4x+2)*2(2x-2)))+(-10x4/(2(4x+2)*2(2x-2)))=0
We calculate terms in parentheses: +(6x2/(2(4x+2)*2(2x-2))), so:
6x2/(2(4x+2)*2(2x-2))
We multiply all the terms by the denominator
6x2
We add all the numbers together, and all the variables
6x^2
Back to the equation:
+(6x^2)
We calculate terms in parentheses: +(-10x4/(2(4x+2)*2(2x-2))), so:
-10x4/(2(4x+2)*2(2x-2))
We multiply all the terms by the denominator
-10x4
We add all the numbers together, and all the variables
-10x^4
We do not support expression: x^4

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