3h(2)=h(2)+18

Solution for 3h(2)=h(2)+18 equation:

3h(2)=h(2)+18

We move all terms to the left:

3h(2)-(h(2)+18)=0

We add all the numbers together, and all the variables

-(+h^2+18)+3h2=0

We add all the numbers together, and all the variables

3h^2-(+h^2+18)=0

We get rid of parentheses

3h^2-h^2-18=0

We add all the numbers together, and all the variables

2h^2-18=0

a = 2; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·2·(-18)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*2}=\frac{-12}{4}
=-3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*2}=\frac{12}{4}
=3
$