3/2(3-x)=1/6(x+3)

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Solution for 3/2(3-x)=1/6(x+3) equation: 



3/2(3-x)=1/6(x+3)

We move all terms to the left:

3/2(3-x)-(1/6(x+3))=0



Domain of the equation: 2(3-x)!=0

x∈R





Domain of the equation: 6(x+3))!=0

x∈R



We add all the numbers together, and all the variables

3/2(-1x+3)-(1/6(x+3))=0

We calculate fractions


(18xx/(2(-1x+3)*6(x+3)))+(-2x0/(2(-1x+3)*6(x+3)))=0



We calculate terms in parentheses: +(18xx/(2(-1x+3)*6(x+3))), so:

18xx/(2(-1x+3)*6(x+3))

We multiply all the terms by the denominator


18xx

Back to the equation:

+(18xx)





We calculate terms in parentheses: +(-2x0/(2(-1x+3)*6(x+3))), so:

-2x0/(2(-1x+3)*6(x+3))

We multiply all the terms by the denominator


-2x0

We add all the numbers together, and all the variables

-2x

Back to the equation:

+(-2x)



We get rid of parentheses

18xx-2x=0

We add all the numbers together, and all the variables

-2x+18xx=0

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